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I can't even get started on a tutorial, when creating a starting point using the "Build an Employee Directory App", the following errors show     Mendix.Modeler.Sprintr.SprintrConnectorException: Error while creating sprintr project. ---> System.ServiceModel.ProtocolException: The remote server returned an unexpected response: (502) Bad Gateway. ---> System.Net.WebException: The remote server returned an error: (502) Bad Gateway. at System.Net.HttpWebRequest.GetResponse() at System.ServiceModel.Channels.HttpChannelFactory`1.HttpRequestChannel.HttpChannelRequest.WaitForReply(TimeSpan timeout) --- End of inner exception stack trace --- Server stack trace: at System.ServiceModel.Channels.HttpChannelUtilities.ValidateRequestReplyResponse(HttpWebRequest request, HttpWebResponse response, HttpChannelFactory`1 factory, WebException responseException, ChannelBinding channelBinding) at System.ServiceModel.Channels.HttpChannelFactory`1.HttpRequestChannel.HttpChannelRequest.WaitForReply(TimeSpan timeout) at System.ServiceModel.Channels.RequestChannel.Request(Message message, TimeSpan timeout) at System.ServiceModel.Dispatcher.RequestChannelBinder.Request(Message message, TimeSpan timeout) at System.ServiceModel.Channels.ServiceChannel.Call(String action, Boolean oneway, ProxyOperationRuntime operation, Object[] ins, Object[] outs, TimeSpan timeout) at System.ServiceModel.Channels.ServiceChannelProxy.InvokeService(IMethodCallMessage methodCall, ProxyOperationRuntime operation) at System.ServiceModel.Channels.ServiceChannelProxy.Invoke(IMessage message) Exception rethrown at [0]: at System.Runtime.Remoting.Proxies.RealProxy.HandleReturnMessage(IMessage reqMsg, IMessage retMsg) at System.Runtime.Remoting.Proxies.RealProxy.PrivateInvoke(MessageData& msgData, Int32 type) at Mendix.Modeler.SprintrConnector.SprintrService.ModelerIntegrationPortType.CreateNewProjectV4(CreateNewProjectV4Request request) at Mendix.Modeler.Sprintr.SprintrConnector.CreateSprintrProjectV4(String projectName, String projectSummary, IEnumerable`1 metadata) in C:\jenkins\workspace\Modeler-Build\modeler\Mendix.Modeler.Core\Sprintr\SprintrConnector.v4.cs:line 33 at Mendix.Modeler.Sprintr.SprintrConnector.CreateProject(String projectName, String projectSummary, IEnumerable`1 metadata) in C:\jenkins\workspace\Modeler-Build\modeler\Mendix.Modeler.Core\Sprintr\SprintrConnector.cs:line 232 --- End of inner exception stack trace --- at Mendix.Modeler.Sprintr.SprintrConnector.HandleSprintrException(Exception e, String actionDescription) in C:\jenkins\workspace\Modeler-Build\modeler\Mendix.Modeler.Core\Sprintr\SprintrConnector.cs:line 258 at Mendix.Modeler.Sprintr.SprintrConnector.CreateProject(String projectName, String projectSummary, IEnumerable`1 metadata) in C:\jenkins\workspace\Modeler-Build\modeler\Mendix.Modeler.Core\Sprintr\SprintrConnector.cs:line 242 at Mendix.Modeler.Sprintr.SprintrProjectCreator.CreateSprintrProject(String projectName, IEnumerable`1 metadata) in C:\jenkins\workspace\Modeler-Build\modeler\Mendix.Modeler.Core\Sprintr\SprintrProjectCreator.cs:line 23 at Mendix.Modeler.ProjectHandling.Creators.ProjectInitializer.<>c__DisplayClass6_0.<AddCreateSprintrProjectStep>b__0(IProgressInfo info) in C:\jenkins\workspace\Modeler-Build\modeler\Mendix.Modeler.ProjectHandling\Creators\ProjectInitializer.cs:line 66 at Mendix.Modeler.Utility.Progress.ProcessRunner.RunStep(Step step) in C:\jenkins\workspace\Modeler-Build\modeler\Mendix.Modeler.UIFramework\Progress\ProcessRunner.cs:line 88 at Mendix.Modeler.Utility.Progress.ProcessRunner.worker_DoWork(Object sender, DoWorkEventArgs e) in C:\jenkins\workspace\Modeler-Build\modeler\Mendix.Modeler.UIFramework\Progress\ProcessRunner.cs:line 68 at System.ComponentModel.BackgroundWorker.OnDoWork(DoWorkEventArgs e) at System.ComponentModel.BackgroundWorker.WorkerThreadStart(Object argument)  

asked 2018-06-25

1 answers